"Two-Letter Card Game" is an analytical counting problem. You are given a set of cards, where each card has two letters. You need to determine how many pairs of cards can be formed such that the two cards in the pair share exactly one letter in the same position. For example, "ab" and "ac" share the first letter 'a' but have different second letters. This problem requires efficient counting and grouping of strings.
Amazon often uses this "Two-Letter Card Game interview question" to test a candidate's ability to use "Hash Tables" for multi-criteria counting. It involves "Enumeration" and combinatorics. Interviewers want to see if you can calculate the number of valid pairs without a comparison, which would be too slow if you have thousands of cards. It's a test of your ability to handle "Combinatorial Explosions" using pre-computed frequencies.
The "Array, Hash Table, Counting, Enumeration, String interview pattern" is the way to go.
XY:
_Y (same second letter, different first).X_ (same first letter, different second).Cards: ["ab", "ac", "ab", "bc"]
A common mistake is forgetting that pairs must share exactly one letter. This means you must exclude cases where both letters match (i.e., the same card type). Another error is over-counting pairs or not handling the frequency of identical cards correctly. Using a simple approach will also fail for large datasets.
To solve the "Two-Letter Card Game coding problem," practice "Frequency-Based Counting." Instead of iterating over every item, iterate over the "Possibility Space" (which for two letters is just ). This shift in perspective is key to optimizing many string and counting problems.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Identify the Largest Outlier in an Array | Medium | Solve | |
| Find the Most Common Response | Medium | Solve | |
| Longest Balanced Substring I | Medium | Solve | |
| Number of Pairs of Strings With Concatenation Equal to Target | Medium | Solve | |
| Sender With Largest Word Count | Medium | Solve |