You are given two arrays of strings, A and B. A string from A is "universal" if every string in B is a subset of it. A string b is a subset of a if every letter in b appears in a, including repeats (e.g., if b has two 'o's, a must have at least two 'o's). You need to return all universal strings in A.
This problem tests your ability to simplify constraints. Comparing every string in A with every string in B is O(A * B). Interviewers at Microsoft and Meta want to see if you can "compress" the requirements of B into a single character count array. This evaluates your skill in Hash Tables and Frequency Counting.
The pattern is Character Frequency Counting.
B, find the maximum frequency of each character required. For example, if B = ["eo", "oo"], the requirement is one 'e' and two 'o's.maxFreqB array of size 26.A, count its characters and check if they satisfy the maxFreqB requirements.A: ["amazon", "apple", "facebook", "google"], B: ["e", "o"].
amazon: 'a': 2, 'm': 1, 'z': 1, 'o': 1, 'n': 1. Missing 'e'. NO.apple: Missing 'o'. NO.facebook: 'f': 1, 'a': 1, 'c': 1, 'e': 1, 'b': 1, 'o': 2, 'k': 1. Has 'e' and 'o'. YES.google: 'g': 2, 'o': 2, 'l': 1, 'e': 1. Has 'e' and 'o'. YES.
Result: ["facebook", "google"].B for every string in A.B.When a problem asks you to compare one set of items against another based on "components" (like letters), look for a way to aggregate the second set into a single "representative" object.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
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| Evaluate the Bracket Pairs of a String | Medium | Solve | |
| Find and Replace Pattern | Medium | Solve |