The "Apply Operations to Make All Array Elements Equal to Zero interview question" is an array-reduction problem. You are given an array of non-negative integers and a window size k. In one operation, you can choose a subarray of length k and decrease all its elements by 1. You need to determine if it's possible to make every element in the array exactly zero using any number of these operations.
Meta asks the "Apply Operations to Make All Array Elements Equal to Zero coding problem" to test a candidate's ability to optimize a greedy strategy. While you could try to simulate the subtractions, an approach is too slow. This problem tests the "Prefix Sum interview pattern" or "Difference Array" technique to handle range updates efficiently.
This problem uses the Greedy and Sliding Window / Difference Array pattern.
arr[0] zero, you must apply arr[0] operations to the first subarray of length k.k elements, you track the "current total subtraction" applied to the current index.arr[i] minus the active_subtractions tells you how many new operations must start at index .k isn't possible, return false.Array: [2, 2, 3, 1, 1], .
arr[0]=2. Start 2 operations for range [0, 2]. current_diff = 2.arr[1]=2. active_subtractions = 2. No new operations needed.arr[2]=3. active_subtractions = 2. Need 1 new operation for range [2, 4]. current_diff = 3.arr[3]=1. Operations from index 0 ended. active_subtractions = 1. No new operations needed.
... continue until all elements are checked.arr[i] < current_active_subtractions. You can't "add" to the array to reach zero.Whenever you see "range updates" (adding or subtracting from a subarray), think of the "Difference Array" or "Prefix Sum" technique. These allow you to handle range operations in time per update.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Minimum Average Difference | Medium | Solve | |
| Maximum Sum Score of Array | Medium | Solve | |
| Count the Hidden Sequences | Medium | Solve | |
| Number of Ways to Split Array | Medium | Solve | |
| Range Addition | Medium | Solve |