The Minimum Average Difference problem asks you to find the index i in an array such that the absolute difference between the average of the first i+1 elements and the average of the remaining elements is minimized. For the last element, the "average of remaining" is considered 0. All averages should be calculated using integer division (rounded down).
This is a standard Minimum Average Difference interview question at Meta and Amazon. It tests a candidate's ability to optimize array calculations using Prefix Sums. It evaluates whether you can avoid complexity by pre-calculating the total sum and updating the "left sum" and "right sum" in a single pass.
The Prefix Sum / Total Sum interview pattern is perfect here.
left_sum = 0.nums[i] to left_sum.right_sum = total_sum - left_sum.left_avg = left_sum // (i + 1).right_avg = right_sum // (n - i - 1) (handle the case where n-i-1 == 0).Array [2, 5, 3, 4], total sum = 14.
i = 0: Left sum = 2, Left avg = 2. Right sum = 12, Right avg = 12/3 = 4. Diff = 2.i = 1: Left sum = 7, Left avg = 7/2 = 3. Right sum = 7, Right avg = 7/2 = 3. Diff = 0.i = 2: Left sum = 10, Left avg = 10/3 = 3. Right sum = 4, Right avg = 4/1 = 4. Diff = 1.
Minimum difference is 0 at index 1.long for sums, leading to overflow errors with large arrays.Whenever a problem involves "left side" and "right side" of an index, the Prefix Sum interview pattern is your first tool. It turns multiple linear scans into lookups. This is a fundamental skill for any coding interview.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Apply Operations to Make All Array Elements Equal to Zero | Medium | Solve | |
| Maximum Sum Score of Array | Medium | Solve | |
| Count the Hidden Sequences | Medium | Solve | |
| Number of Ways to Split Array | Medium | Solve | |
| Range Addition | Medium | Solve |