The "Chalkboard XOR Game interview question" is a mathematical game played with an array of numbers. Two players take turns removing one number from the chalkboard. A player loses if the XOR sum of all remaining numbers on the board is 0 after their move. However, if the XOR sum is already 0 at the start of a player's turn, that player wins immediately. You need to determine if the first player will win, assuming both play optimally.
This "Chalkboard XOR Game coding problem" is a high-level Brainteaser asked by companies like Google to test a candidate's mathematical intuition and ability to find invariants in a system. It evaluates whether you can move beyond simulation and find a logical "short-circuit" answer based on the properties of the XOR operation and the game's rules.
This problem follows the Game Theory and Bit Manipulation interview pattern. The solution relies on two key observations:
Array: [1, 1, 2]
[1, 1], XOR sum is 0. Player 1 loses. If they remove 1, board is [1, 2], XOR sum is 3. Player 2 then removes either 1 or 2, making XOR sum non-zero for themselves? No, this requires deep optimal play analysis, but the pattern boils down to: "If XOR sum != 0 and length is odd, Player 1 loses."When you see XOR combined with a game, think about the properties of XOR. It is commutative, associative, and . Many "Game Theory interview pattern" problems involving XOR have simple solutions based on parity or initial sums.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Bitwise OR of All Subsequence Sums | Medium | Solve | |
| Find XOR Sum of All Pairs Bitwise AND | Hard | Solve | |
| Minimum Operations to Make Array Elements Zero | Hard | Solve | |
| Maximum Number of Moves to Kill All Pawns | Hard | Solve | |
| Bitwise XOR of All Pairings | Medium | Solve |