The Maximum Number of Moves to Kill All Pawns coding problem places a knight on a chessboard at a given position, with pawns scattered across the board. Two players alternate turns. On each turn, the current player moves the knight to the nearest pawn (by BFS moves) and removes it. The first player maximizes total moves; the second player minimizes. Find the total number of knight moves made, assuming both play optimally.
Google uses this problem because it combines BFS for shortest knight paths, bitmask DP for subset states, and game theory (minimax). It's a complete challenge testing multiple algorithmic competencies simultaneously. Candidates must precompute pawn-to-pawn distances and then apply game-theory DP on the bitmask of remaining pawns.
BFS precomputation + Bitmask Game Theory DP:
dp[mask][last] = optimal total moves when the set of remaining pawns is mask and the knight is currently at pawn last. Player 1 maximizes, player 2 minimizes, alternating based on the number of pawns already captured (parity of bits cleared).p in mask, dp[mask][last] = best(dp[mask ^ (1<<p)][p] + dist[last][p]) where best = max if current turn is player 1, min if player 2.Starting pos: (0,0). Pawns: [(1,2), (2,4)].
For the Array Math Bitmask Breadth-First Search Game Theory Bit Manipulation interview pattern, this problem combines three independent skills: BFS, bitmask DP, minimax. Master each separately before combining. The bitmask DP for TSP-like problems (visiting all nodes) with game theory is a common hard interview pattern at Google.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Chalkboard XOR Game | Hard | Solve | |
| The Number of Good Subsets | Hard | Solve | |
| Count the Number of Square-Free Subsets | Medium | Solve | |
| Find Sum of Array Product of Magical Sequences | Hard | Solve | |
| Find XOR Sum of All Pairs Bitwise AND | Hard | Solve |