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Design Circular Deque

Medium
12.5%
Updated 8/1/2025

Design Circular Deque

1. What is this problem about?

The Design Circular Deque interview question asks you to implement a Double-Ended Queue (Deque) using a fixed-size array. A deque allows adding and removing elements from both the front and the rear. The "circular" requirement means that when you reach the end of the array, you should wrap around to the beginning, making full use of the allocated space.

2. Why is this asked in interviews?

Companies like Meta and Amazon ask this to test your mastery of Array interview patterns and modulo arithmetic. It evaluates your ability to manage pointers and handle edge cases like "Full" and "Empty" states in a constrained environment. It’s a core systems-programming task.

3. Algorithmic pattern used

This problem uses Circular Buffer logic.

  • Maintain front and rear pointers.
  • Use a size variable to easily track if the deque is full or empty.
  • insertFront: front = (front - 1 + capacity) % capacity.
  • insertLast: rear = (rear + 1) % capacity.
  • deleteFront: front = (front + 1) % capacity.
  • deleteLast: rear = (rear - 1 + capacity) % capacity.

4. Example explanation

Capacity = 3.

  1. insertLast(1): [1, _, _]. front=0, rear=0.
  2. insertLast(2): [1, 2, _]. front=0, rear=1.
  3. insertFront(3): [1, 2, 3]. front = (0-1+3)%3 = 2. rear=1.
    • Note: 3 was placed at the end of the array because the "front" wrapped around.
  4. getFront(): Returns element at index 2 (value 3).
  5. isFull(): Returns true.

5. Common mistakes candidates make

  • Pointer Confusion: Incrementing front when you should be decrementing it (or vice versa).
  • Modulo Errors: Forgetting to add the capacity before taking the modulo when decrementing pointers (e.g., (i - 1) % n can be negative in some languages).
  • State Tracking: Failing to differentiate between an empty queue and a full queue when both pointers end up at the same position.

6. Interview preparation tip

Always use a count or size variable. It makes the isEmpty() and isFull() methods trivial and prevents you from having to do complex logic comparing the front and rear pointers.

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