The Design Front Middle Back Queue interview question asks you to implement a specialized queue that allows insertion and removal of elements from three distinct points: the front, the exact middle, and the back. Defining the "middle" can be tricky depending on whether the current size is even or odd. This Design Front Middle Back Queue coding problem tests your ability to maintain balance within a linear structure during frequent modifications.
Companies like Meta and Amazon ask this to evaluate your ability to manage Dynamic Data Structures. It tests your proficiency with Linked List interview patterns or the use of Two Deques to represent a single logical queue. It’s a test of pointer arithmetic and structural consistency.
The most efficient approach is the Two-Deque Pattern.
left and right.left.size() == right.size() or left.size() == right.size() - 1.left deque.right deque.left or front of right depending on the total size parity.left and right if they become unbalanced.Queue: [1, 2, 3, 4]. left: [1, 2], right: [3, 4].
pushMiddle(10): Since sizes are equal, we can push to the front of right.
left: [1, 2], right: [10, 3, 4].popMiddle(): Remove from the front of right (it's the larger one).
left: [1, 2], right: [3, 4].pushFront(5): left: [5, 1, 2], right: [3, 4].
right. left: [5, 1], right: [2, 3, 4].popMiddle call when the total size is odd.pushMiddle (), which is too slow.Whenever you see a "Middle" requirement in a data structure, consider splitting the structure in half. This "divide and manage" strategy is the foundation for efficient median tracking and specialized queues.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Design Circular Deque | Medium | Solve | |
| Design Circular Queue | Medium | Solve | |
| Moving Average from Data Stream | Easy | Solve | |
| First Unique Number | Medium | Solve | |
| Design Hit Counter | Medium | Solve |