The Design HashMap interview question asks you to implement a key-value store from scratch without using any built-in library hash tables. You need to support put(key, value), get(key), and remove(key). This Design HashMap coding problem is a fundamental test of how well you understand the internals of data structures, specifically collision handling and indexing.
Tech giants like Apple, Google, and Microsoft ask this to verify your understanding of Hash Function interview patterns. It evaluates whether you know how to map a large range of keys to a smaller array size and how to handle two keys mapping to the same index (collisions). It's a deep dive into computer science fundamentals.
This problem is typically solved using Separate Chaining.
key % size to find the index.put: Find the index, traverse the list to update an existing key, or append a new pair.get: Find the index, traverse the list to find the key.remove: Find the index, traverse and remove the node from the linked list.Bucket size = 10.
put(1, 100): . Add (1, 100) to Bucket 1.put(11, 200): . Bucket 1 already has (1, 100). Add (11, 200) to the same bucket (Chaining).get(11): Go to Bucket 1, see 1 is not 11, move to next, found 11. Return 200.remove(1): Go to Bucket 1, find node with key 1, remove it.Learn the difference between Separate Chaining and Open Addressing (like linear probing). Being able to compare their performance under load shows that you understand the practical engineering challenges of high-performance data storage.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Design HashSet | Easy | Solve | |
| Design Phone Directory | Medium | Solve | |
| Delete Nodes From Linked List Present in Array | Medium | Solve | |
| Finding Pairs With a Certain Sum | Medium | Solve | |
| Linked List Components | Medium | Solve |