The Design HashSet interview question is similar to the HashMap problem but focuses solely on unique keys. You need to implement a set that supports add(key), remove(key), and contains(key). The key challenge is ensuring that adding the same key multiple times has no additional effect, and checking for existence is fast. This Design HashSet coding problem evaluates your ability to implement deduplication logic.
Companies like Meta and Amazon ask this to test your knowledge of Hash Table interview patterns. It’s a foundational exercise in managing a collection where membership is the primary concern. It evaluates your ability to use boolean arrays or bitsets for small ranges, and hashing for large ones.
This is usually implemented with Hashing with Buckets.
add: Hash the key, check the corresponding bucket. If the key isn't already there, add it.contains: Hash the key, search the bucket for the key.remove: Hash the key, find and delete the key from the bucket if it exists.add(1): Key 1 hashed to bucket 1. Success.add(2): Key 2 hashed to bucket 2. Success.contains(1): Returns true.add(1): Key 1 hashed to bucket 1. It's already there! No change.remove(2): Key 2 found in bucket 2 and removed.boolean[1000001] works for integer keys, it's not a generalizable solution for other types of keys (like strings) and uses excessive memory.contains check becomes instead of average.Practice calculating the Load Factor (Number of elements / Number of buckets). Discussing how you would resize the internal array when it gets too full is a great way to demonstrate advanced understanding of data structure scaling.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Design HashMap | Easy | Solve | |
| Design Phone Directory | Medium | Solve | |
| Delete Nodes From Linked List Present in Array | Medium | Solve | |
| Finding Pairs With a Certain Sum | Medium | Solve | |
| Linked List Components | Medium | Solve |