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Find the Count of Monotonic Pairs I

Hard
67.8%
Updated 6/1/2025

Find the Count of Monotonic Pairs I

What is this problem about?

The Find the Count of Monotonic Pairs I interview question asks you to count the number of pairs of arrays (arr1,arr2)(arr1, arr2) such that:

  1. Both arrays have the same length as a given array nums.
  2. arr1[i]+arr2[i]=nums[i]arr1[i] + arr2[i] = nums[i] for all ii.
  3. arr1arr1 is monotonically non-decreasing.
  4. arr2arr2 is monotonically non-increasing. Your goal is to find the total number of such valid pairs modulo 109+710^9 + 7.

Why is this asked in interviews?

Companies like Google ask the Find the Count of Monotonic Pairs coding problem to test your proficiency with Dynamic Programming. It’s a sophisticated counting problem where each choice at index ii is constrained by the choice at index i1i-1. It evaluations your ability to handle state transitions and multi-variable constraints.

Algorithmic pattern used

This problem is solved using Dynamic Programming.

  1. State Definition: dp[i][v] is the number of valid pairs for the first i elements where arr1[i] = v.
  2. Transitions: To find dp[i][v], we look at all valid dp[i-1][prev_v].
  • Condition for arr1: prev_vvprev\_v \leq v.
  • Condition for arr2: nums[i1]prev_vnums[i]vnums[i-1] - prev\_v \geq nums[i] - v.
  1. Logic: These two conditions define a range of valid prev_v values.
  2. Summation: The total count is the sum of dp[n-1][v] for all possible v[0,nums[n1]]v \in [0, nums[n-1]].

Example explanation

nums = [2, 3]

  • Index 0: arr1[0] can be 0, 1, 2. dp[0][0]=1, dp[0][1]=1, dp[0][2]=1.
  • Index 1: nums[1] = 3. Try arr1[1] = 2.
  • arr2[1] = 3 - 2 = 1.
  • Need arr1[0] \leq 2 and arr2[0] \geq 1.
  • Possible arr1[0] values: 0, 1, 2.
  • Check arr2[0]: 20=212-0=2 \geq 1 (OK), 21=112-1=1 \geq 1 (OK), 22=0<12-2=0 < 1 (NO).
  • So dp[1][2] = dp[0][0] + dp[0][1] = 2.

Common mistakes candidates make

  • O(NMax2)O(N \cdot Max^2) Complexity: Using a nested loop to sum previous DP states without optimization, which might be too slow for large values of nums[i].
  • Modulo: Forgetting to apply modulo 109+710^9 + 7 at each addition.
  • Constraint handling: Missing one of the two monotonicity requirements during the transition phase.

Interview preparation tip

For DP problems involving sums of previous states, always think about Prefix Sums. If you can calculate the sum of dp[i-1] in O(1)O(1) using a prefix sum array, you can reduce the overall complexity from O(NM2)O(N \cdot M^2) to O(NM)O(N \cdot M).

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