The Find the Count of Monotonic Pairs II interview question is the optimized version of the monotonic pairs challenge. The rules are identical: find pairs where increases, decreases, and . However, the constraints on and are significantly larger ( and respectively), requiring a highly efficient solution.
BNY Mellon and other financial firms use the Find the Count of Monotonic Pairs II coding problem to test a candidate's ability to optimize Dynamic Programming transitions. It separates candidates who can write a basic DP from those who can use advanced techniques like Prefix Sum optimization or Difference Arrays to achieve time complexity.
This problem relies on DP with Prefix Sum Optimization.
prev_v <= min(v, v - (nums[i] - nums[i-1])).prev_v <= v - diff.dp[i-1] for all values.dp[i-1].dp[i][v] is simply the prefix sum of dp[i-1] up to the index v - diff.nums = [2, 5]. .
dp[0] prefix sums: [1, 2, 3] (for values 0, 1, 2).dp[1][4]:v = 4, diff = 3.prev_v \leq 4 - 3 = 1.dp[1][4] = prefixSum[1] = 2.
Pairs: (arr1:[0, 4], arr2:[2, 1]) and (arr1:[1, 4], arr2:[1, 1]).v - diff is less than zero before accessing the prefix sum array.Master DP state optimization. Whenever your DP transition involves summing a range of values from the previous step, a prefix sum array is almost always the intended way to optimize it. This is a core Prefix Sum interview pattern.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Find the Count of Monotonic Pairs I | Hard | Solve | |
| Kth Smallest Instructions | Hard | Solve | |
| Number of Sets of K Non-Overlapping Line Segments | Medium | Solve | |
| Number of Sub-arrays With Odd Sum | Medium | Solve | |
| Count Ways to Make Array With Product | Hard | Solve |