The Find the Index of the Large Integer coding problem is a unique "interactive" challenge. You are given an array where all integers are equal except for one "large" integer. You cannot access the array elements directly. Instead, you are provided with an API called ArrayReader that can compare the sums of two sub-ranges of the array. Your goal is to find the index of this single larger integer using the minimum number of API calls.
Amazon and other top-tier companies use this Interactive interview question to test a candidate's ability to apply Binary Search in a non-standard environment. It requires more than just searching for a value; it requires logic to narrow down a search space based on relative comparisons. This simulates real-world "black box" testing or scenarios where retrieving data is expensive, and you must minimize the number of queries.
The core pattern is Binary Search. Because you need to find one specific element among many identical ones, you can split the current search range into two or three parts. By comparing the sums of the left half and the right half, you can determine which side contains the larger integer. If the sums are equal (in the case of an odd number of elements where one is left out), the larger integer must be the one that was excluded from the comparison.
Imagine an array of 5 elements: [2, 2, 5, 2, 2].
compare(0, 1, 2, 3).compare(2, 2, 3, 3).Whenever you see a problem where you need to find one element in a sorted or nearly uniform collection, think "Decrease and Conquer." Practice how to handle "odd vs even" splits in binary search. Visualizing the array as a balance scale helps immensely with this specific problem.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Number of Equal Numbers Blocks | Medium | Solve | |
| Search in a Sorted Array of Unknown Size | Medium | Solve | |
| Find in Mountain Array | Hard | Solve | |
| Leftmost Column with at Least a One | Medium | Solve | |
| Maximum Font to Fit a Sentence in a Screen | Medium | Solve |