The "Leftmost Column with at Least a One interview question" is an interactive problem involving a binary matrix. In this matrix, each row is sorted in non-decreasing order (meaning all 0s come before all 1s). You cannot access the matrix directly; instead, you use an API to query individual cells. Your goal is to find the index of the leftmost column that contains at least one '1'. If no such column exists, return -1. This "Leftmost Column with at Least a One coding problem" challenges you to minimize the number of API calls.
Companies like Uber and Meta ask this to test your ability to optimize search strategies in a constrained environment. It's a great test of "Binary Search interview pattern" and "Matrix interview pattern" knowledge. Because you are limited in how you can access the data, you must think about the structure of the matrix to avoid unnecessary queries.
There are two main approaches. One is performing a Binary Search on each row to find the first '1'. However, the more optimized approach is the "Staircase Search" or "Top-Right to Bottom-Left" traversal. You start at the top-right corner. If you see a '0', move down (since this row won't have a '1' further left). If you see a '1', move left to see if there's an even earlier '1' in another row. This ensures an O(M + N) complexity, where M is rows and N is columns.
Matrix: [[0, 0, 1], [0, 1, 1], [0, 0, 0]]
Whenever you see a matrix where rows or columns are sorted, think about how you can "navigate" the grid rather than just scanning it. The staircase walk is a very powerful technique for sorted matrices.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Find the Index of the Large Integer | Medium | Solve | |
| Find a Peak Element II | Medium | Solve | |
| Search a 2D Matrix | Medium | Solve | |
| Median of a Row Wise Sorted Matrix | Medium | Solve | |
| Number of Equal Numbers Blocks | Medium | Solve |