The "Linked List Cycle II interview question" is an extension of the basic cycle detection problem. Not only do you need to determine if a cycle exists, but you must also find the exact node where the cycle begins. If no cycle exists, return null. This "Linked List Cycle II coding problem" requires a deeper mathematical understanding of the two-pointer approach.
Companies like Meta and Amazon ask this to see if a candidate can derive or remember the mathematical relationship between the meeting point and the cycle's entrance. It tests "Linked List interview pattern" proficiency and the ability to refine a "Two Pointers interview pattern" into a multi-step algorithm.
The pattern is still Floyd's Tortoise and Hare, but with an extra phase.
head of the list and keep the other at the meeting point. Move both pointers one step at a time. The node where they meet again is the start of the cycle.
This works because of the mathematical distance relationships within a looped linked list.List: 3 -> 2 -> 0 -> -4, and -4 points back to 2.
L1 = n*C - L2).Practice the derivation of the distance formula for this problem. Understanding the math behind it makes it much easier to remember and implement during a high-pressure interview.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Intersection of Two Linked Lists | Easy | Solve | |
| Linked List Cycle | Easy | Solve | |
| Delete the Middle Node of a Linked List | Medium | Solve | |
| Partition List | Medium | Solve | |
| Remove Duplicates from Sorted List II | Medium | Solve |