This problem involves a simple but iterative process of shrinking a string. You are allowed to perform the following operation as many times as possible:
Your task is to find the minimum length of the string after performing these operations repeatedly.
This is a classic Two Pointers problem often used by Amazon and Goldman Sachs. It evaluates:
The Two Pointers pattern is perfect here:
left = 0 and right = length - 1.left < right and s[left] == s[right]:
char = s[left].left forward as long as s[left] == char.right backward as long as s[right] == char.max(0, right - left + 1).String: caaaac
left = 0 ('c'), right = 5 ('c'). They match.left: skips index 0. left is now 1.right: skips index 5. right is now 4.aaaa.left = 1 ('a'), right = 4 ('a'). They match.left: skips indices 1, 2, 3, 4. left is now 5.right: skips index 4, 3, 2, 1. right is now 0.left > right, so we stop. Result: 0.while loops correctly when the pointers cross, leading to negative lengths or crashes.Always walk through your Two Pointers logic with a very short string (1-3 characters) to ensure your loop conditions (left < right) and final length calculations are correct.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Reverse Words in a String II | Medium | Solve | |
| Make String a Subsequence Using Cyclic Increments | Medium | Solve | |
| Valid Palindrome IV | Medium | Solve | |
| Magical String | Medium | Solve | |
| Compare Version Numbers | Medium | Solve |