The Minimum Swaps to Group All 1's Together problem gives you a binary array containing only 0s and 1s. Your task is to find the minimum number of swap operations needed to move all the 1s into one contiguous group. A swap exchanges any two elements. This Minimum Swaps to Group All 1's Together coding problem is a clean application of the fixed-size sliding window technique on binary arrays.
Microsoft, TikTok, and Expedia ask this because it tests whether candidates can reframe an operation-based problem into an observation-based one. Instead of simulating swaps directly, the insight is to count how many 1s need to move into a target window. The array and sliding window interview pattern is fundamental here, and this problem is an ideal gateway to a whole class of window-based optimization challenges.
The approach is a fixed-size sliding window. Count the total number of 1s in the array — call it k. This is the window size (since all 1s must fit in a contiguous segment of length k). Slide a window of size k across the array. For each window, count how many 0s are inside — those 0s represent 1s that need to swap in from outside. Track the minimum zero-count across all windows.
Array: [0, 1, 0, 1, 1, 0, 0]. Total 1s = 3. Window size = 3.
"Minimum swaps to group elements" problems almost always reduce to a sliding window of size equal to the target element count. Once you internalize this reframing, you can solve the entire family of problems: grouping 0s, grouping specific values, or grouping elements satisfying a condition. After this problem, practice the circular variant (the array wraps around) to strengthen your ability to adapt linear algorithms to circular constraints.
| Title | Difficulty | Topics | LeetCode |
|---|---|---|---|
| Minimum Swaps to Group All 1's Together | Medium | Solve | |
| Minimum Swaps to Group All 1's Together II | Medium | Solve | |
| Alternating Groups II | Medium | Solve | |
| Count Subarrays Where Max Element Appears at Least K Times | Medium | Solve | |
| Grumpy Bookstore Owner | Medium | Solve |